Tag: Bridge Rectifier

bridge rectifier

  • 220Vac SMPS Input Smoothing Capacitor Sizing: Calculation and Simulation Example

    220Vac SMPS Input Smoothing Capacitor Sizing: Calculation and Simulation Example

    For smoothing capacitors, after calculating capacitance from the allowable ripple, tolerance and minimum bus voltage must be verified. Taking a 60W SMPS with bridge-rectified 220Vac as an example, this article walks through the calculation and examines ripple and charging current using rectified waveforms.

    The previous article ‘How to Select a Smoothing Capacitor’ covered voltage ratings and selection principles using Schade curves. Here, the initial capacitance is determined using the energy equation for a constant-power load. The numerical values are based on the conditions of the design example.

    1. Design Conditions: 220Vac, 60W, Ripple 40Vpp

    The target circuit consists of a single-phase bridge rectifier without PFC and an input bulk capacitor. The connection sequence is AC source → source resistance → bridge rectifier → bulk capacitor and DC/DC input load. The capacitor’s ESR is included in series, and the bus DC return is separated from protective earth. Because this calculation example deals with a high-voltage non-isolated section directly connected to utility power, it is structured as an example for circuit operation verification and numerical analysis.

    Parameter Example Condition
    Rated Input and Variation 220Vac ±10%, i.e., 198~242Vac
    Line Frequency 50/60Hz, capacitance calculation based on 50Hz
    DC/DC Output Power 60W
    DC/DC Stage Efficiency Assumed to be 85%
    Allowable Bus Ripple 40Vpp
    Capacitor Initial Capacitance Tolerance −20%
    Bridge Voltage Drop for Calculation Sum of two conducting diodes 2V

    The 220Vac case serves as an appropriate baseline to explain the operation of line-operated SMPS. However, 85~264Vac universal input or PFC buses operate in different operating regimes and require separate calculations. The allowable ripple of 40Vpp is the target value for this design, and whether the downstream DC/DC can operate stably even at the ripple valley must be verified against the actual converter’s input range.

    2. Constant-Power Loads Are Calculated Using Energy Equations

    Assuming the DC/DC maintains output power, the average power drawn from the bus is as follows. Here, 85% is the efficiency assumed to evaluate the conversion power of the DC/DC stage, excluding losses in the bridge and input stage.

    \[ P_{\mathrm{bus}}=\frac{P_{\mathrm{out}}}{\eta_{\mathrm{DC/DC}}} =\frac{60}{0.85}\approx70.59\,\mathrm{W} \]

    Because the bus current is \(I=P_{\mathrm{bus}}/V_{\mathrm{bus}}\), it increases as the voltage drops during discharge. Therefore, rather than fixing a single current value in \(C=I\Delta t/\Delta V\) assuming a constant current, it is more appropriate to use the capacitor’s energy change.

    \[ P_{\mathrm{bus}}\Delta t=\frac{1}{2}C_{\mathrm{eff}} \left(V_{\mathrm{hi}}^2-V_{\mathrm{lo}}^2\right),\qquad C_{\mathrm{eff}}=\frac{2P_{\mathrm{bus}}\Delta t}{V_{\mathrm{hi}}^2-V_{\mathrm{lo}}^2} \]

    The ripple frequency of full-wave rectification is twice the line frequency. First, neglecting the charging time, the discharge time is taken as \(\Delta t\approx1/(2f_{\mathrm{line}})\), which is 10ms at 50Hz. This is a conservative 1st-order approximation with a longer discharge time to quickly estimate the initial capacitance. Appendix A of Power Integrations AN-92 also calculates the bulk capacitor from the energy balance of a constant-power load while the rectifier is blocked.

    At the low line input of 198Vac, the calculated charging peak and target minimum voltage are as follows.

    \[ V_{\mathrm{hi}}\approx198\sqrt{2}-2=278.01\,\mathrm{V},\qquad V_{\mathrm{lo}}=278.01-40=238.01\,\mathrm{V} \]

    \[ C_{\mathrm{eff,min}}\approx \frac{2\times70.59\times0.010}{278.01^2-238.01^2} \approx68.4\,\mu\mathrm{F} \]

    Applying an initial tolerance of −20%, a nominal capacitance of \(C_{\mathrm{nom}}\ge68.4/0.8\approx85.5\,\mu\mathrm{F}\) is required. Therefore, 100µF is selected as the initial candidate. Here, the initial tolerance is applied to establish a 1st candidate; in an actual design, the final margin is confirmed by also accounting for capacitance variation over temperature and operating lifetime.

    3. Compare Candidate Capacitances Using Minimum Effective Values

    Ripple can be recalculated and compared using the equation below. The effective capacitance in the comparison table is 80% of the nominal value, and the same low-line peak of 278.01V is used in the approximate calculation.

    \[ V_{\mathrm{lo}}\approx\sqrt{V_{\mathrm{hi}}^2- \frac{2P_{\mathrm{bus}}}{2f_{\mathrm{line}}C_{\mathrm{eff}}}},\qquad \Delta V_{\mathrm{pp}}=V_{\mathrm{hi}}-V_{\mathrm{lo}} \]

    Nominal Capacitance −20% Effective Capacitance 50Hz Approximate Ripple 60Hz Approximate Ripple 50Hz Simulated Ripple
    68µF 54.4µF 51.4Vpp 42.1Vpp 40.4Vpp
    82µF 65.6µF 41.9Vpp 34.4Vpp 33.7Vpp
    100µF 80µF 33.8Vpp 27.8Vpp 27.8Vpp
    120µF 96µF 27.8Vpp 23.0Vpp 23.2Vpp

    Under the approximation criteria, 82µF exceeds the 50Hz·40Vpp target, whereas 100µF satisfies it. Applying the effective capacitance of 80µF for the 100µF candidate yields an approximate 50Hz ripple of about 33.8Vpp and a minimum voltage of about 244.2V. At 60Hz, the recharge interval becomes shorter, reducing the ripple. The simulated values in the table reflect the circuit conditions described in the next section.

    4. How Much Do Circuit Waveforms Differ from Calculated Values?

    220Vac bridge rectifier, source resistance, smoothing capacitor with series ESR, and constant-power DC/DC input load
    Bridge rectifier and smoothing circuit for 220Vac input. The DC return is separated from protective earth.

    The waveforms below show transient simulation results of the bridge rectifier circuit performed in ngspice. The input source resistance is assumed to be 2Ω, and the capacitor ESR is assumed to be 0.5Ω. All four diodes use the same generic model. The model parameters are IS=5nA, N=1.8, RS=0.1Ω, BV=1000V, and IBV=10µA. Rather than being restricted to specific commercial components, the modeling is intended to verify fundamental circuit behavior.

    The load is an averaged constant-power model with \(I_{\mathrm{load}}=70.59/V_{\mathrm{bus}}\). To ensure startup calculation stability, the denominator was clamped below 200V, and the load was ramped up gradually over 50~55ms. The results were evaluated during the steady state at 0.5~0.6 seconds. In this interval, it was verified that the bus remains above 200V and load power maintains its setpoint. The maximum simulation timestep is 20µs. Behavioral sources and transient analysis methods can be referenced in the ngspice manual.

    198Vac · 50Hz · Effective 80µF Parameter Simulation Result
    Maximum Bus Voltage Approx. 277.1V
    Minimum Bus Voltage Approx. 249.3V
    Bus Ripple Approx. 27.8Vpp
    Capacitor Low-Frequency Ripple Current Approx. 0.654Arms
    Bridge Output Peak Charging Current Approx. 2.43A
    Input AC voltage and bus voltage plotted on the same voltage axis. 2 cycles (40ms) of 50Hz input AC, effective capacitance 80µF.
    Input AC voltage and bus voltage plotted on the same voltage axis. 2 cycles (40ms) of 50Hz input AC, effective capacitance 80µF.

    The simulated circuit value of 27.8Vpp is smaller than the simple calculated value of 33.8Vpp. This occurs because the rectifier conducts for a finite interval to supply the load and charge the capacitor, resulting in a shorter discharge duration than the calculation that assumes discharge over the entire half-cycle. Conversely, source resistance and diode forward drops reduce the achievable peak voltage. ST AN1262 also takes rectifier conduction time into account when evaluating input bulk capacitance and minimum bus voltage.

    Even if the 82µF candidate falls within 40Vpp in circuit simulation, adopting it immediately is premature. The resistance and diode parameters here are assumed values. It is safer to select the initial candidate using a conservative 1st-order calculation and then refine it using models and measurements reflecting actual components and operating conditions.

    Bridge output current, capacitor current, and load current. Positive capacitor current represents charging, negative represents discharging, and high-frequency switching currents are not included.
    Bridge output current, capacitor current, and load current. Positive capacitor current represents charging, negative represents discharging, and high-frequency switching currents are not included.

    The capacitor current is \(i_C=i_{\mathrm{bridge}}-i_{\mathrm{load}}\). It delivers current to the load during discharge and receives pulsating currents during charging. Therefore, allowable ripple current for the capacitor cannot be evaluated solely from the load current. The RMS value above represents the low-frequency component calculated as \(I_{C,\mathrm{rms}}=\sqrt{(1/T)\int i_C^2dt}\). The averaged load model does not include the high-frequency switching current of the DC/DC converter.

    5. Voltage Rating and Ripple Current Are Verified Separately

    At the high line input of 242Vac, the no-load peak calculated without diode forward drop is \(V_{\mathrm{pk,max}}\approx242\sqrt{2}=342.2\,\mathrm{V}\). Based on this steady-state voltage, 400V and 450V ratings can be compared as candidates. When determining the actual voltage rating, surge margins, voltage derating guidelines, and operating temperature must be comprehensively evaluated in addition to the steady-state peak.

    Ripple current ratings must be compared against the datasheet frequency and temperature specifications. A simple calculation of only the low-frequency ESR loss in this model gives \(P_{\mathrm{ESR}}\approx0.654^2\times0.5\approx0.214\,\mathrm{W}\). Actual dissipation must also account for frequency-dependent ESR and high-frequency current components. Temperature and lifetime considerations can be explored further in the article on smoothing capacitor lifetime, thermal management, layout, and venting. When increasing capacitance, startup inrush current and rectifier stress must also be verified.

    The ripple target must also be distinguished from holdup time. The 10ms in this 50Hz calculation is the periodic interval between rectification peaks. This differs from the requirement of maintaining output for 20ms following an AC line dropout. Holdup is evaluated separately using \(t_{\mathrm{hold}}\approx C_{\mathrm{eff}}(V_{\mathrm{start}}^2-V_{\mathrm{stop}}^2)/(2P_{\mathrm{bus}})\), which must incorporate the case where power drops out at the worst-case ripple valley and the downstream converter’s actual minimum operating voltage.

    6. Selection Results for This Example

    Under the conditions of 220Vac ±10%, 60W, DC/DC efficiency of 85%, 50/60Hz, and allowable ripple of 40Vpp, 100µF can be selected as the initial capacitance candidate. With an effective capacitance of 80µF reflecting the −20% tolerance, the approximate 50Hz ripple is about 33.8Vpp, and the circuit simulation value is about 27.8Vpp.

    After determining the 1st candidate capacitance by calculation, the criteria to check when finalizing component selection are as follows.

    • Verify that at low line (198Vac), the ripple valley remains above the minimum input voltage of the downstream DC/DC converter.
    • Determine a voltage rating (400V or 450V) that satisfies surge margins and derating standards based on the high line (242Vac) no-load peak voltage (342.2V).
    • Check whether temperature rise due to low-frequency ripple and high-frequency switching components, as well as startup inrush current, can be tolerated.
  • How to select a bridge rectifier diode

    How to select a bridge rectifier diode

    Characteristics of Diodes

    As shown in the figure, a diode is a component that can allow current to flow only in the direction of ▶. This is a nonlinear relationship in which the forward current \( V_{F} \) rapidly increases when a voltage is applied across the diode above the forward voltage \( V_{F} \). In addition, when the forward current \( I_{F} \) flows, a forward voltage drop \( V_{F} \) must occur.

    Since power loss occurs at this time, attention should be paid to component heating in a high-current rectification circuit. When the diode is heated, leakage current increases, and there is a risk of fire due to thermal runaway. Therefore, most diode plastic molds meet the flame retardant standard of UL94V-0 or higher.

    Diode Forward Voltage(\( V_{F} \)) – Forward Current(\( I_{F} \))Characteristic

    Select the Reverse Maximum Voltage \(V_{RM}\) of the bridge diode

    In the bridge rectification circuit, while the diode is conducting, the applied voltage \( e\) of each diode terminal voltage \(V_{D}\) becomes \(\sqrt{2}\times e_{rms}\). In reality, if the input voltage of the AC fluctuates, \( e_{rms}\) also changes in proportion to it, so that \(V_{D}\) should not exceed the reverse maximum voltage \(V_{RM}\) of the diode even at the maximum input voltage.

    In addition, since the actual rectification circuit has the influence of external noise such as surges, \(V_{RM}\) should be selected sufficiently. In general, a Reverse voltage of twice the rectified voltage is selected, and if the applied voltage is unstable, a higher Reverse voltage selection is required.


    Selection of forward current \(I_{F}\) for bridge diode

    In a typical rectifying circuit, the current \(i_{c}\) flowing through the diode flows in a pulse waveform rather than a sine wave. This pulse current has a maximum value that changes under various conditions.

    First, since the average value \(I_{ave}\) of \(i_{c}\) flowing through the diode must be equal to the DC current \(I_{O}\) after rectification, if the period of half-cycle is \(T\), and the period of current flowing is \(t_{1}\), it becomes \(\frac{1}{T}\int_{0}^{t_{1}}i_{c}dt=I_{0}\).

    Relation of RMS and Peak to Average Diode Current in Capacitor-input Circuits
    From O.H Schade, Proc. IRE, Vol. 31, 1943, p. 356

    In general, the forward current \(I_{F}\) of a rectifying diode is maximum rated from the average value of this \(i_{c}\). However, this is the value when the current flows in direct current, and the pulse current should be considered low in the rated value. The maximum value \(i_{CP}\) of this pulsed current can be obtained from O.H. Schade’s graph. (n\) of \(n\omega CR_{L}\) on the horizontal axis has a coefficient of 0.5 at double voltage rectification, 1 at half-wave rectification, and 2 at full-wave rectification. \(C\) is the capacitor capacity, and \(R_{L}\) is the load resistance value.

    Next, \(R_{S}/\left ( nR_{L} \right )\) of the vertical axis means a ratio of the load resistance and the line impedance. The line impedance \(R_{S}\) should be considered to include not only the resistance value of the wiring but also the winding resistance of the power transformer.

    Under these conditions, the values of the left vertical axis are read from the graph below. This value multiplied by the output current \(I_{O}\) is the maximum current value \(i_{CP}\).


    Selection of diodes considering surge current

    Another current condition of the diode is surge current \(I_{FSM}\). In the rectifying circuit, when the power switch is initially operated, the charging voltage of the capacitor is set to 0V. Therefore, at the moment when the switch is operated, a large charging current flows to the capacitor. This is called the inrush current, and the terminal voltage of the capacitor is increased by this large charging current, and accordingly, the current value of the charging gradually becomes a normal state.

    In general, the surge current \(I_{FSM}\) of a rectifying diode has a value of about 10 times that of forward current \(I_{F}\). However, this is a guarantee value of one cycle and the value decreases when the temperature of the diode is high.


    Power loss of diode

    The diode suffers power loss due to the forward voltage drop \(V_{F}\) and the forward current \(I_{F}\). And as a result, it generates heat and increases the temperature. Silicon diodes currently in general must not exceed the maximum junction temperature \(T_{j(max)}\) 150℃. Since the current rating of the diode is determined under the condition of reaching the junction temperature, it is necessary to install a heatsink to lower the temperature when the temperature is high.

    It is not easy to calculate the power loss of a diode strictly. The simple calculation method is calculated by multiplying the output current \(I_{O}\) after rectification at the forward voltage drop \(V_{F}\) as the loss. In addition, in a bridge diode, the total loss should be doubled because current always flows through two diodes.

  • Type of rectifier according to the number of diodes

    Type of rectifier according to the number of diodes


    A half-wave rectifier with one diode

    Commercial power is a sinusoidal wave of 50/60 Hz, which is a symmetrical waveform of positive and negative voltages at every half of the frequency. Rectifying only a positive voltage with one diode is called a half-wave rectifier.

    At this time, the diode charges the capacitor with a positive voltage and prevents the charge in the opposite direction by reverse voltage to the diode in a negative voltage cycle. In this case, the direct current output current \( I_{O} \) is an average value of the capacitor charging current \( i_{C} \) and \( I_{O}=\frac{1}{T}\int_{0}^{t}i_{C}dt \).

    As such, in a half-wave rectifier, the charging current \(i_{C} \) of the capacitor is charged only once per cycle of the power supply frequency, so the current maximum \(i_{C,peak} \) gets that big. Therefore, if the output current is large, the half-wave rectifier has a large capacitor to reduce the output ripple. Therefore, it should only be used in circuits with small output currents.

    Half-wave rectifier

    A full-wave rectifier with two diodes

    The full-wave rectifier uses two diodes to rectify both positive and negative voltages of sine waves. A full-wave rectifier using two diodes requires two windings around the center tap of the transformer on the secondary side. In each transformer winding, diode \(D_{1}\) turn-on in the positive half cycle, and diode \(D_{2}\) turn-on in the negative half cycle. Therefore, the rectified waveform is a pulse waveform in which the negative half-period of the sine wave is inverted.

    Full-wave rectifier

    A full-wave rectifier with four diodes(Bridge Diode)

    The most commonly used is a full-wave rectifier using four diodes, also called a bridge rectifier. Four diodes should be used instead of one trans-winding, but it is not a big drawback because many bridge diodes with four diodes packaged are on the market.

    The current in the positive and negative half cycles alternately charges the capacitor, so it is fully rectified, but two diodes are inserted in series in the current path, which doubles the forward voltage drop \(V_{F} \) of the diode and increases the loss.

    For example, let calculate the efficiency of a 12W circuit with a rectified voltage of 12V and an output current of 1A. If the forward voltage drop \(V_{F} \) of the diode is 1V, for full-wave rectification using the center tap,

    $$\eta = \frac{12W}{\left ( 12V + 1V_{F} \right )\times 1A}=92\%$$

    For full-wave rectifier using a bridge diode,

    $$\eta = \frac{12W}{\left ( 12V + 2V_{F} \right )\times 1A}=86\%$$

    There is a big difference in efficiency.

    Despite these shortcomings, bridge rectifier are widely used because the center tap of the transformer can be removed and the circuit can be simplified using commercially available bridge diodes.

    Bridge rectifier

    Use a rectifier suitable for the purpose of the circuit

    As above, each rectifier has clear disadvantages and advantages. If one diode is used, the circuit is simple, but because the charging current of the capacitor is large, it must be used for small output, and if two diodes are used, the efficiency is high, but the center tab of the transformer has to be designed. Bridge diodes are simple to design, but efficiency should be consider the forward voltage drop of the diodes.

    Recently, synchronous rectifier, which are methods of rectifying using FET instead of diodes, have been used for high efficiency, but this will be explained later.